What is the integral of (x^2)/((x-2)) ?

The integral of (x^2)/((x-2)) is ((x-2)^2)/2+4(x-2)+4ln|x-2|+C

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integral of (x^2)/((x-2))

\int \frac{x ^{2}}{( x - 2 )} d x

\frac{( x - 2 ) ^{2}}{2} + 4 (x - 2) + 4 ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x ^{2}}{x - 2} d x

Apply u-substitution

: \int \frac{( u + 2 ) ^{2}}{u} d u

= \int \frac{( u + 2 ) ^{2}}{u} d u

Expand

\frac{( u + 2 ) ^{2}}{u} : u + 4 + \frac{4}{u}

= \int u + 4 + \frac{4}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u d u + \int 4 d u + \int \frac{4}{u} d u

\int u d u = \frac{u ^{2}}{2}

\int 4 d u = 4 u

\int \frac{4}{u} d u = 4 ln ∣ u ∣

= \frac{u ^{2}}{2} + 4 u + 4 ln ∣ u ∣

Substitute back

u = x - 2

= \frac{( x - 2 ) ^{2}}{2} + 4 (x - 2) + 4 ln ∣ x - 2 ∣

Add a constant to the solution

= \frac{( x - 2 ) ^{2}}{2} + 4 (x - 2) + 4 ln ∣ x - 2 ∣ + C

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What is the integral of (x^2)/((x-2)) ?
The integral of (x^2)/((x-2)) is ((x-2)^2)/2+4(x-2)+4ln|x-2|+C