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Popular >

y^'=((y-x))/x

Solution

y^{^{'}} = \frac{( y - x )}{x}

Solution

y = - ln (x) x + c_{1} x

Solution steps

y^{'} (x) = \frac{( y - x )}{x}

Solve linear ODE:

y = - ln (x) x + c_{1} x

y = - ln (x) x + c_{1} x

Popular Examples

derivative of f(x)=6x^{-1}derivative of

f (x) = 6 x^{- 1}

derivative of cos^2(1-2x)

\frac{d}{d x} (cos^{2} (1 - 2 x))

(dy)/(dx)=((2y+5)/(8x+9))^2

\frac{d y}{d x} = (\frac{2 y + 5}{8 x + 9})^{2}

inverse oflaplace 4/(s^2-9)inverse laplace

\frac{4}{s ^{2} - 9}

integral of 1/(x(x-9)^2)

\int \frac{1}{x ( x - 9 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=((y-x))/x ?
The solution for y^'=((y-x))/x is y=-ln(x)x+c_{1}x