What is the integral from 1 to infinity of 1/(1+e^x) ?

The integral from 1 to infinity of 1/(1+e^x) is diverges

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integral from 1 to infinity of 1/(1+e^x)

\int_{1}^{\infty} \frac{1}{1 + e ^{x}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{1 + e ^{x}} d x

Compute the indefinite integral:

\int \frac{1}{1 + e ^{x}} d x = - ln ∣ 1 + e^{x} ∣ + x + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{1 + e ^{x}} d x =

diverges

= diverges

2 x, 5, \frac{2}{x ^{2}}

x \to \infty lim (2 x - 4 x^{2} - 2 x)

\int \frac{1}{2 x + 2} d x

5^{t}

\int 2 z ln (y) d z

What is the integral from 1 to infinity of 1/(1+e^x) ?
The integral from 1 to infinity of 1/(1+e^x) is diverges