What is the sum from n=0 to infinity of 1/(3^n-n) ?

The sum from n=0 to infinity of 1/(3^n-n) is converges

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sum from n=0 to infinity of 1/(3^n-n)

n = 0 \sum \infty \frac{1}{3 ^{n} - n}

converges

Solution steps

n = 0 \sum \infty \frac{1}{3 ^{n} - n}

Apply Series Ratio Test:

converges

= converges

x^{y}

y = x^{2} 2 x - 7

\int (2 x^{2} + 1) e^{(x^{2})} d x

x \frac{d y}{d x} = \frac{1}{y ^{3}}

q^{^{''}} + 2 q^{^{'}} + \frac{1}{0.25} q = 50 cos (3 t)

What is the sum from n=0 to infinity of 1/(3^n-n) ?
The sum from n=0 to infinity of 1/(3^n-n) is converges