What is the derivative of f(t)= 1/((t^2+3t+1)^{5/2)} ?

The derivative of f(t)= 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}

What is the first derivative of f(t)= 1/((t^2+3t+1)^{5/2)} ?

The first derivative of f(t)= 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}

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derivative of

f (t) = \frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}}

- \frac{5 ( 2 t + 3 )}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}}

Solution steps

\frac{d}{d t} (\frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((t^{2} + 3 t + 1)^{- \frac{5}{2}})

Apply the chain rule:

- \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} \frac{d}{d t} (t^{2} + 3 t + 1)

= - \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} \frac{d}{d t} (t^{2} + 3 t + 1)

\frac{d}{d t} (t^{2} + 3 t + 1) = 2 t + 3

= - \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} (2 t + 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{5 ( 2 t + 3 )}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}}

\int 1 - e^{x} d x

x \to - \infty lim (x^{3} - x)

x \to \infty lim (x^{- 6})

\int - x \cdot e^{3 x} d x

\int x^{2} - y^{2} d y

What is the derivative of f(t)= 1/((t^2+3t+1)^{5/2)} ?
The derivative of f(t)= 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}
What is the first derivative of f(t)= 1/((t^2+3t+1)^{5/2)} ?
The first derivative of f(t)= 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}