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Popular >

y^'+4y=0

Solution

y^{^{'}} + 4 y = 0

Solution

y = e^{- 4 t + c_{1}}

Solution steps

y^{'} (t) + 4 y = 0

Solve separable ODE:

y = e^{- 4 t + c_{1}}

y = e^{- 4 t + c_{1}}

Popular Examples

sum from n=1 to infinity of 8(7/8)^n

n = 1 \sum \infty 8 (\frac{7}{8})^{n}

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\int 18 x^{2} (6 x^{3} + 5)^{\frac{1}{2}} d x

integral of tan^2(x)(sec^2(x)-1)

\int tan^{2} (x) (sec^{2} (x) - 1) d x

derivative of (x^3+x^{3/2})

\frac{d}{d x} ((x^{3} + x)^{\frac{3}{2}})

derivative of 2^{cos(x})

\frac{d}{d x} (2^{c o s (x)})

Frequently Asked Questions (FAQ)

What is the solution for y^'+4y=0 ?
The solution for y^'+4y=0 is y=e^{-4t+c_{1}}