What is the integral from 1 to 13 of 4x^{-2} ?

The integral from 1 to 13 of 4x^{-2} is 48/13

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integral from 1 to 13 of 4x^{-2}

\int_{1}^{13} 4 x^{- 2} d x

\frac{48}{13}

Decimal Notation

3.69230 \dots

Solution steps

\int_{1}^{13} 4 x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{13} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{13}

= 4 [- \frac{1}{x}]_{1}^{13}

Compute the boundaries:

\frac{12}{13}

= 4 \cdot \frac{12}{13}

Simplify

= \frac{48}{13}

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What is the integral from 1 to 13 of 4x^{-2} ?
The integral from 1 to 13 of 4x^{-2} is 48/13