What is laplacetransform 2t^2-e^{-1} ?

The answer to laplacetransform 2t^2-e^{-1} is 4/(s^3)-1/(es)

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laplacetransform 2t^2-e^{-1}

laplace transform

2 t^{2} - e^{- 1}

\frac{4}{s ^{3}} - \frac{1}{es}

Solution steps

L {2 t^{2} - e^{- 1}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 2 L {t^{2}} - L {e^{- 1}}

L {t^{2}} : \frac{2}{s ^{3}}

L {e^{- 1}} : \frac{1}{es}

= 2 \cdot \frac{2}{s ^{3}} - \frac{1}{es}

Refine

2 \frac{2}{s ^{3}} - \frac{1}{es} : \frac{4}{s ^{3}} - \frac{1}{es}

= \frac{4}{s ^{3}} - \frac{1}{es}

n = 1 \sum \infty \frac{1}{4}

f (x) = \frac{x ^{2}}{x + 2}, at x = 2

\int y^{2} e^{x y^{2}} d x

\frac{d}{d x} (4 - x^{2} + 2 arcsin (\frac{x}{2}))

\frac{x ^{2}}{x - 3}

What is laplacetransform 2t^2-e^{-1} ?
The answer to laplacetransform 2t^2-e^{-1} is 4/(s^3)-1/(es)