What is the integral from 2 to infinity of 7x^{-2} ?

The integral from 2 to infinity of 7x^{-2} is 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of 7x^{-2}

\int_{2}^{\infty} 7 x^{- 2} d x

\frac{7}{2}

Decimal Notation

3.5

Solution steps

\int_{2}^{\infty} 7 x^{- 2} d x

Compute the indefinite integral:

\int 7 x^{- 2} d x = - \frac{7}{x} + C

Compute the boundaries:

\int_{2}^{\infty} 7 x^{- 2} d x = 0 - (- \frac{7}{2})

= 0 - (- \frac{7}{2})

Simplify

= \frac{7}{2}

\frac{\partial}{\partial x} (x - y^{2})

x \to 0 lim (3^{x})

\int x^{3} 7 + x^{4} d x

x^{6}, x^{7}

\int_{0}^{\frac{π}{4}} tan^{4} (x) d x

What is the integral from 2 to infinity of 7x^{-2} ?
The integral from 2 to infinity of 7x^{-2} is 7/2