What is the solution for y^{''}-2y^'+y=e^{2x} ?

The solution for y^{''}-2y^'+y=e^{2x} is y=c_{1}e^x+c_{2}xe^x+e^{2x}

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y^{''}-2y^'+y=e^{2x}

y^{^{''}} - 2 y^{^{'}} + y = e^{2 x}

y = c_{1} e^{x} + c_{2} x e^{x} + e^{2 x}

Solution steps

y^{''} (x) - 2 y^{'} (x) + y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} x e^{x} + e^{2 x}

y = c_{1} e^{x} + c_{2} x e^{x} + e^{2 x}

\int_{0}^{l n (19)} x e^{x} d x

\int t sin (n t) d t

\frac{\partial}{\partial x} (cot (x))

\frac{5}{x}

\frac{d}{d x} (\frac{1}{( x - 6 ) ^{2}})

What is the solution for y^{''}-2y^'+y=e^{2x} ?
The solution for y^{''}-2y^'+y=e^{2x} is y=c_{1}e^x+c_{2}xe^x+e^{2x}