What is the tangent of f(x)=x^2+3x+4pi,\at x=2.5 ?

The tangent of f(x)=x^2+3x+4pi,\at x=2.5 is y=8x+6.31637…

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tangent of f(x)=x^2+3x+4pi,\at x=2.5

tangent of

f (x) = x^{2} + 3 x + 4 π, at x = 2.5

y = 8 x + 6.31637 \dots

Solution steps

Find the tangent point:

(2.5, 4 π + 13.75)

Find the slope of

f (x) = x^{2} + 3 x + 4 π : \frac{df ( x )}{d x} = 2 x + 3

Compute the slope of

f (x) = x^{2} + 3 x + 4 π

x = 2.5 : m = 8

Find the line with slope m=

8

and passing through

(2.5, 4 π + 13.75) : y = 8 x + 6.31637 \dots

y = 8 x + 6.31637 \dots

\frac{\partial}{\partial y} (2 sin (x) + sin (x + y))

x \to 0 lim (\frac{( 0 )}{x})

\frac{d y}{d x} + 5 y = 6

\int \frac{1}{( 4 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (- x^{3} + 5 a x^{2} - 3 a^{2} x - b)

What is the tangent of f(x)=x^2+3x+4pi,\at x=2.5 ?
The tangent of f(x)=x^2+3x+4pi,\at x=2.5 is y=8x+6.31637…