What is laplacetransform 4sin(pit) ?

The answer to laplacetransform 4sin(pit) is (4pi)/(s^2+pi^2)

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laplacetransform 4sin(pit)

laplace transform

4 sin (π t)

\frac{4 π}{s ^{2} + π ^{2}}

Solution steps

L {4 sin (π t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (π t)}

L {sin (π t)} : \frac{π}{s ^{2} + π ^{2}}

= 4 \cdot \frac{π}{s ^{2} + π ^{2}}

Refine

4 \frac{π}{s ^{2} + π ^{2}} : \frac{4 π}{s ^{2} + π ^{2}}

= \frac{4 π}{s ^{2} + π ^{2}}

\int x^{3} - 3 x^{- 4} + 5 d x

\frac{d}{d x} (xx)

\int_{- 1}^{1} 6 - 6 x^{2} d x

\frac{d y}{d x} = 10 y e^{x + 6}

\frac{d}{d x} (\frac{e ^{x}}{5 - x})

What is laplacetransform 4sin(pit) ?
The answer to laplacetransform 4sin(pit) is (4pi)/(s^2+pi^2)