What is the derivative of (x^3/3-4x+1) ?

The derivative of (x^3/3-4x+1) is x^2-4

What is the first derivative of (x^3/3-4x+1) ?

The first derivative of (x^3/3-4x+1) is x^2-4

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Popular >

\frac{d}{d x} (\frac{x ^{3}}{3} - 4 x + 1)

x^{2} - 4

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= x^{2} - 4 + 0

Simplify

= x^{2} - 4

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = 3 + e^{\frac{x}{2}}

\frac{d}{d x} (4 x^{3} + 2)

\int 2 e^{2 x} sec^{3} (e^{2 x}) d x

x \to 1 + lim (\frac{x - 1}{x - 3})

\int_{0}^{1} 1 + 36 x d x

What is the derivative of (x^3/3-4x+1) ?
The derivative of (x^3/3-4x+1) is x^2-4
What is the first derivative of (x^3/3-4x+1) ?
The first derivative of (x^3/3-4x+1) is x^2-4