What is the derivative of 9x^{7/5}-5x^2+10^4 ?

The derivative of 9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5

What is the first derivative of 9x^{7/5}-5x^2+10^4 ?

The first derivative of 9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5

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\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

- 10 x + \frac{63 x ^{\frac{2}{5}}}{5}

Solution steps

\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

Simplify

9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4} : 9 x^{\frac{7}{5}} - 5 x^{2} + 10000

= \frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 10000)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{\frac{7}{5}}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (10000)

\frac{d}{d x} (9 x^{\frac{7}{5}}) = \frac{63 x ^{\frac{2}{5}}}{5}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (10000) = 0

= \frac{63 x ^{\frac{2}{5}}}{5} - 10 x + 0

Simplify

= - 10 x + \frac{63 x ^{\frac{2}{5}}}{5}

x \to 0 + lim (- x + 7)

\frac{d ^{2} y}{d x ^{2}} = e^{5 x^{2}}

\frac{d}{d t} (\frac{tan ^{2} ( 3 t )}{t ^{2} + sec ^{2} ( t ) + 1})

f (x) = 4 - x^{2} - ln (\frac{1}{2} x + 1) (0.4)

\int e^{- θ} cos (3 θ) d θ

What is the derivative of 9x^{7/5}-5x^2+10^4 ?
The derivative of 9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5
What is the first derivative of 9x^{7/5}-5x^2+10^4 ?
The first derivative of 9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5