What is the derivative of f(r)= 3/(r^3) ?

The derivative of f(r)= 3/(r^3) is -9/(r^4)

What is the first derivative of f(r)= 3/(r^3) ?

The first derivative of f(r)= 3/(r^3) is -9/(r^4)

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derivative of

f (r) = \frac{3}{r ^{3}}

- \frac{9}{r ^{4}}

Solution steps

\frac{d}{d r} (\frac{3}{r ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d r} (\frac{1}{r ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d r} (r^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 3 r^{- 3 - 1})

Simplify

3 (- 3 r^{- 3 - 1}) : - \frac{9}{r ^{4}}

= - \frac{9}{r ^{4}}

n = 1 \sum \infty \frac{x ^{n}}{n 3 ^{n}}

\int 3 x^{5} + 4 x d x

f (x) = \frac{4}{x + 1}

\frac{d}{d x} (\frac{( 2 x + 1 ) ^{5}}{x ^{2} + 1})

f (x) = x + \frac{4}{x}, at x = 4

What is the derivative of f(r)= 3/(r^3) ?
The derivative of f(r)= 3/(r^3) is -9/(r^4)
What is the first derivative of f(r)= 3/(r^3) ?
The first derivative of f(r)= 3/(r^3) is -9/(r^4)