What is the derivative of y=3x^2+2 ?

The derivative of y=3x^2+2 is 6x

What is the first derivative of y=3x^2+2 ?

The first derivative of y=3x^2+2 is 6x

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derivative of

y = 3 x^{2} + 2

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2) = 0

= 6 x + 0

Simplify

= 6 x

\int (\frac{1}{2} - \frac{1}{2} cos (2 θ - \frac{π}{4})) d θ

1 + 0.2 t

\frac{d ^{4}}{d x ^{4}} (8 e^{- 4 x})

\frac{d y}{d x} = y (3 - y), y (0.2) = 8

\int 6 x^{2} e^{2 x} d x

What is the derivative of y=3x^2+2 ?
The derivative of y=3x^2+2 is 6x
What is the first derivative of y=3x^2+2 ?
The first derivative of y=3x^2+2 is 6x