What is the first derivative of 5x+7 ?

The first derivative of 5x+7 is 5

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derivative of 5x+7

\frac{d}{d x} (5 x + 7)

5

Solution steps

\frac{d}{d x} (5 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) + \frac{d}{d x} (7)

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= 5 + 0

Simplify

= 5

y^{^{'}} + 2 t y = 0

x \to 0 lim (\frac{ln ( e + x ) - 1}{x})

t y^{^{'}} = t^{2} - t - 2 y

\frac{d}{d x} (\frac{x ^{3}}{x - 2})

\int 9 sin^{3} (x) cos^{5} (x) d x