What is the sum from n=1 to infinity of (n+4)/(3n+2) ?

The sum from n=1 to infinity of (n+4)/(3n+2) is diverges

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sum from n=1 to infinity of (n+4)/(3n+2)

n = 1 \sum \infty \frac{n + 4}{3 n + 2}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 4}{3 n + 2}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of (n+4)/(3n+2) ?
The sum from n=1 to infinity of (n+4)/(3n+2) is diverges