What is the sum from n=1 to infinity of (n+1)/(n+2) ?

The sum from n=1 to infinity of (n+1)/(n+2) is diverges

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sum from n=1 to infinity of (n+1)/(n+2)

n = 1 \sum \infty \frac{n + 1}{n + 2}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 1}{n + 2}

Apply Series Divergence Test:

diverges

= diverges

x \to 4 lim (\frac{x - 2}{x})

\frac{d}{d t} (s t)

\frac{d}{d x} ((3 x - 1)^{5} (1 - 3 x)^{4})

\int \frac{x ^{2}}{1 - 4 x ^{2}} d x

x \to \infty lim (4 \cdot x)

What is the sum from n=1 to infinity of (n+1)/(n+2) ?
The sum from n=1 to infinity of (n+1)/(n+2) is diverges