What is the derivative of sin(4t) ?

The derivative of sin(4t) is cos(4t)*4

What is the first derivative of sin(4t) ?

The first derivative of sin(4t) is cos(4t)*4

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derivative of

sin (4 t)

cos (4 t) \cdot 4

Solution steps

\frac{d}{d t} (sin (4 t))

Apply the chain rule:

cos (4 t) \frac{d}{d t} (4 t)

= cos (4 t) \frac{d}{d t} (4 t)

\frac{d}{d t} (4 t) = 4

= cos (4 t) \cdot 4

5^{- x}

\int \frac{38}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (\frac{( a x + b y )}{( c x + d y )})

\frac{( 3 x + 5 ) ( 2 x - 7 )}{8 x ^{2} - 3}

\frac{\partial}{\partial x} (x y - 3 f (x, y) - f (x, y) x^{2} + f (x, y) y)

What is the derivative of sin(4t) ?
The derivative of sin(4t) is cos(4t)*4
What is the first derivative of sin(4t) ?
The first derivative of sin(4t) is cos(4t)*4