What is the derivative of f(x)=3x^2+6x ?

The derivative of f(x)=3x^2+6x is 6x+6

What is the first derivative of f(x)=3x^2+6x ?

The first derivative of f(x)=3x^2+6x is 6x+6

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derivative of

f (x) = 3 x^{2} + 6 x

6 x + 6

Solution steps

\frac{d}{d x} (3 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

= 6 x + 6

x \to - 2 lim (3 - 5 x^{2})

\frac{\partial}{\partial x} (\frac{1}{2 π} arctan (\frac{x}{y}))

y^{^{'}} = \frac{x y}{x ^{2} - 1}

(- 7, - 9), (1, 3)

\int_{1}^{e^{2}} \frac{ln ^{4} ( x ^{2} )}{x} d x

What is the derivative of f(x)=3x^2+6x ?
The derivative of f(x)=3x^2+6x is 6x+6
What is the first derivative of f(x)=3x^2+6x ?
The first derivative of f(x)=3x^2+6x is 6x+6