What is the tangent of f(x)=-x^2+4 ?

The tangent of f(x)=-x^2+4 is y=-2a_{0}x+a_{0}^2+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=-x^2+4

tangent of

f (x) = - x^{2} + 4

y = - 2 a_{0} x + a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - a_{0}^{2} + 4)

Find the slope of

f (x) = - x^{2} + 4 : \frac{df ( x )}{d x} = - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2 a_{0}

Find the line with slope m=

- 2 a_{0}

and passing through

(a_{0}, - a_{0}^{2} + 4) : y = - 2 a_{0} x + a_{0}^{2} + 4

y = - 2 a_{0} x + a_{0}^{2} + 4

sin (x) + \frac{4}{5} cot (x)

f (x) = 3 x^{2} - 4 x + 1, at x = 2

\int (2 u^{2} - 2 u^{- 1}) d u

3 y^{^{''}} + 2 y^{^{'}} + y = 0

\frac{\partial}{\partial y} (\frac{y}{( x ^{2} + y ^{2} )})

What is the tangent of f(x)=-x^2+4 ?
The tangent of f(x)=-x^2+4 is y=-2a_{0}x+a_{0}^2+4