What is (\partial)/(\partial z)(x^{y/z}) ?

The answer to (\partial)/(\partial z)(x^{y/z}) is -(yx^{y/z}ln(x))/(z^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(x^{y/z})

\frac{\partial}{\partial z} (x^{\frac{y}{z}})

- \frac{y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

Solution steps

\frac{\partial}{\partial z} (x^{\frac{y}{z}})

Treat

x, y

as constants

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{\frac{y}{z}} = e^{\frac{y}{z} l n (x)}

= \frac{\partial}{\partial z} (e^{\frac{y}{z} l n (x)})

Apply the chain rule:

e^{\frac{y}{z} l n (x)} \frac{\partial}{\partial z} (\frac{y}{z} ln (x))

= e^{\frac{y}{z} l n (x)} \frac{\partial}{\partial z} (\frac{y}{z} ln (x))

\frac{\partial}{\partial z} (\frac{y}{z} ln (x)) = - \frac{y ln ( x )}{z ^{2}}

= e^{\frac{y}{z} l n (x)} (- \frac{y ln ( x )}{z ^{2}})

Simplify

e^{\frac{y}{z} l n (x)} (- \frac{y ln ( x )}{z ^{2}}) : - \frac{y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

= - \frac{y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

f (x) = 2 x^{3} \cdot ln (7 x)

\frac{d}{d x} (\frac{4 x ^{2} + 3}{2 x - 1})

f (x) = x^{3} + y^{3} = 16

x = 5 - 5 \cdot y^{2}, x = 5 \cdot y^{2} - 5

\frac{d}{d x} (\frac{x ^{4} + 48}{24 x})

What is (\partial)/(\partial z)(x^{y/z}) ?
The answer to (\partial)/(\partial z)(x^{y/z}) is -(yx^{y/z}ln(x))/(z^2)