What is inverse oflaplace (e^{-pis})/s ?

The answer to inverse oflaplace (e^{-pis})/s is \H(t-pi)

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inverse oflaplace (e^{-pis})/s

inverse laplace

\frac{e ^{- π s}}{s}

H (t - π)

Solution steps

L^{- 1} {\frac{e ^{- π s}}{s}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Where

H (t)

is Heaviside step function

= H (t - π) L^{- 1} {\frac{1}{s}} (t - π)

L^{- 1} {\frac{1}{s}} : H (t)

= H (t - π) H (t - π)

= H (t - π)

x^{2} - 3 x, 3 x + 7, - 1, 7

\frac{d}{d t} (2^{t})

\int \frac{1}{y} e^{- \frac{x}{y}} d x

sin (x^{2})

\frac{\partial}{\partial x} (y^{3} sin (x + y))

What is inverse oflaplace (e^{-pis})/s ?
The answer to inverse oflaplace (e^{-pis})/s is \H(t-pi)