What is (\partial)/(\partial y)(sqrt(4-x^2-5y^2)) ?

The answer to (\partial)/(\partial y)(sqrt(4-x^2-5y^2)) is -(5y)/(sqrt(4-x^2-5y^2))

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(\partial)/(\partial y)(sqrt(4-x^2-5y^2))

\frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

- \frac{5 y}{4 - x ^{2} - 5 y ^{2}}

Solution steps

\frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 4 - x ^{2} - 5 y ^{2}} \frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

= \frac{1}{2 4 - x ^{2} - 5 y ^{2}} \frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

\frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2}) = - 10 y

= \frac{1}{2 4 - x ^{2} - 5 y ^{2}} (- 10 y)

Simplify

\frac{1}{2 4 - x ^{2} - 5 y ^{2}} (- 10 y) : - \frac{5 y}{4 - x ^{2} - 5 y ^{2}}

= - \frac{5 y}{4 - x ^{2} - 5 y ^{2}}

\frac{\partial}{\partial x} (5 e^{x})

\frac{s - 3}{s ^{2} - 4 s + 3}

x \to 0 lim (\frac{ln ( x ^{2} + 1 )}{x})

x^{2}, x - 4, - 4, 4

f (x) = \frac{1}{10} x - \frac{1}{6}

What is (\partial)/(\partial y)(sqrt(4-x^2-5y^2)) ?
The answer to (\partial)/(\partial y)(sqrt(4-x^2-5y^2)) is -(5y)/(sqrt(4-x^2-5y^2))