What is the tangent of 3x^2+3x-5 ?

The tangent of 3x^2+3x-5 is y=(6a_{0}+3)x-3a_{0}^2-5

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tangent of 3x^2+3x-5

tangent of

3 x^{2} + 3 x - 5

y = (6 a_{0} + 3) x - 3 a_{0}^{2} - 5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} + 3 a_{0} - 5)

Find the slope of

y = 3 x^{2} + 3 x - 5 : \frac{d y}{d x} = 6 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0} + 3

Find the line with slope m=

6 a_{0} + 3

and passing through

(a_{0}, 3 a_{0}^{2} + 3 a_{0} - 5) : y = (6 a_{0} + 3) x - 3 a_{0}^{2} - 5

y = (6 a_{0} + 3) x - 3 a_{0}^{2} - 5

\frac{\partial}{\partial x} (\frac{2 x}{y})

y = x^{4} e^{3 x}

n = 5 \sum \infty \frac{1}{n ^{2} + n}

\int_{0}^{\frac{π}{3}} cos (4 x) d x

n = 1 \sum \infty (- 1)^{n + 1} \frac{2}{n + 1}

What is the tangent of 3x^2+3x-5 ?
The tangent of 3x^2+3x-5 is y=(6a_{0}+3)x-3a_{0}^2-5