What is the tangent of y=x^4+9x^2-x,(1,9) ?

The tangent of y=x^4+9x^2-x,(1,9) is y=21x-12

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tangent of y=x^4+9x^2-x,(1,9)

tangent of

y = x^{4} + 9 x^{2} - x, (1, 9)

y = 21 x - 12

Solution steps

Find the slope of

y = x^{4} + 9 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 18 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 21

Find the line with slope m=

21

and passing through

(1, 9) : y = 21 x - 12

y = 21 x - 12

e^{x + y} - y^{^{'}} = 0

\frac{d y}{d x} = (x - 2 y cot (2 x))

\int \frac{7 x}{x ^{3} - 4} d x

\int (\frac{x - 4}{x ^{9}}) d x

y = (x - 2)^{2}, y = 4 - x, y = 2 x - 2

What is the tangent of y=x^4+9x^2-x,(1,9) ?
The tangent of y=x^4+9x^2-x,(1,9) is y=21x-12