What is the sum from n=0 to infinity of (6/5)^{-n} ?

The sum from n=0 to infinity of (6/5)^{-n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (6/5)^{-n}

n = 0 \sum \infty (\frac{6}{5})^{- n}

converges

Solution steps

n = 0 \sum \infty (\frac{6}{5})^{- n}

Apply Series Ratio Test:

converges

= converges

f (x) = x + 1, at x = 5

\int \frac{x}{4 x - 3} d x

\int_{0}^{\frac{π}{6}} 2 sec^{3} (x) d x

\int 1 - e^{- x} d x

\int_{1}^{7} \frac{x + 1}{x ^{2} + 2 x - 1} d x

What is the sum from n=0 to infinity of (6/5)^{-n} ?
The sum from n=0 to infinity of (6/5)^{-n} is converges