What is the derivative of 3^x*ln(3) ?

The derivative of 3^x*ln(3) is ln^2(3)*3^x

What is the first derivative of 3^x*ln(3) ?

The first derivative of 3^x*ln(3) is ln^2(3)*3^x

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\frac{d}{d x} (3^{x} \cdot ln (3))

ln^{2} (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} ln (3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (3) \frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= ln (3) \cdot 3^{x} ln (3)

Simplify

ln (3) \cdot 3^{x} ln (3) : ln^{2} (3) \cdot 3^{x}

= ln^{2} (3) \cdot 3^{x}

\int_{4}^{\infty} e^{- \frac{x}{5}} d x

a^{2} + 4 a + 5

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\frac{d}{d x} (sin (∣ x ∣))

\int \frac{( x ^{4} - 2 x ^{3} + 1 )}{x ^{2}} d x

What is the derivative of 3^x*ln(3) ?
The derivative of 3^x*ln(3) is ln^2(3)*3^x
What is the first derivative of 3^x*ln(3) ?
The first derivative of 3^x*ln(3) is ln^2(3)*3^x