What is laplacetransform te^{-,\at} ?

The answer to laplacetransform te^{-,\at} is e^{-,\at} 1/(s^2)

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laplacetransform te^{-,\at}

laplace transform

t e^{-, at}

e^{-, at} \frac{1}{s ^{2}}

Solution steps

L {e^{-, at} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{-, at} L {t}

L {t} : \frac{1}{s ^{2}}

= e^{-, at} \frac{1}{s ^{2}}

\int_{0}^{2} x 2 x - x^{2} d x

x \to 0 + lim (ln^{2} (x) - ln (x))

\frac{d}{d x} (\frac{sec ^{2} ( x ^{3} )}{2})

\frac{\partial}{\partial x} (x sin (5 x^{2} y))

\int - 2 sin^{5} (x) cos^{2} (x) d x

What is laplacetransform te^{-,\at} ?
The answer to laplacetransform te^{-,\at} is e^{-,\at} 1/(s^2)