What is the limit as x approaches-0 of e^{1/x} ?

The limit as x approaches-0 of e^{1/x} is diverges

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limit as x approaches-0 of e^{1/x}

x \to - 0 lim (e^{\frac{1}{x}})

diverges

Solution steps

x \to - 0 lim (e^{\frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 0 + lim (e^{\frac{1}{x}}) = \infty

x \to - 0 - lim (e^{\frac{1}{x}}) = 0

= diverges

\frac{d}{d x} (c^{1} cos (x) + c^{2} sin (x))

x \to - 4 lim (12 x + 1)

\int \frac{1}{x ln ^{2} ( x ) + 1} d x

\int \frac{4 x}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d θ} (sec^{2} (m θ))

What is the limit as x approaches-0 of e^{1/x} ?
The limit as x approaches-0 of e^{1/x} is diverges