What is the integral from 0 to 1 of (77)/(x^5) ?

The integral from 0 to 1 of (77)/(x^5) is diverges

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integral from 0 to 1 of (77)/(x^5)

\int_{0}^{1} \frac{77}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{77}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 77 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 77 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int_{- 1}^{1} π (7 - 7 x^{2})^{2} d x

\frac{d}{d x} (\frac{8 x ^{2} + 6 x + 2}{x})

\frac{\partial}{\partial x} (55 x - 0.5 x^{2})

\int \frac{- x - 1}{x ^{2} + 9} d x

\frac{t d y}{d t} + 3 y = t^{4}, t > 0, y (1) = 3

What is the integral from 0 to 1 of (77)/(x^5) ?
The integral from 0 to 1 of (77)/(x^5) is diverges