What is the derivative of ln(1-x^3) ?

The derivative of ln(1-x^3) is -(3x^2)/(1-x^3)

What is the first derivative of ln(1-x^3) ?

The first derivative of ln(1-x^3) is -(3x^2)/(1-x^3)

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\frac{d}{d x} (ln (1 - x^{3}))

- \frac{3 x ^{2}}{1 - x ^{3}}

Solution steps

\frac{d}{d x} (ln (1 - x^{3}))

Apply the chain rule:

\frac{1}{1 - x ^{3}} \frac{d}{d x} (1 - x^{3})

= \frac{1}{1 - x ^{3}} \frac{d}{d x} (1 - x^{3})

\frac{d}{d x} (1 - x^{3}) = - 3 x^{2}

= \frac{1}{1 - x ^{3}} (- 3 x^{2})

Simplify

\frac{1}{1 - x ^{3}} (- 3 x^{2}) : - \frac{3 x ^{2}}{1 - x ^{3}}

= - \frac{3 x ^{2}}{1 - x ^{3}}

\int 2 + \frac{1}{x ^{2}} d x

\frac{d}{d x} ((1 - 4 x)^{- 1})

g (x) = 6^{x}

\frac{\partial}{\partial x} (7 x^{3} y^{2})

\frac{\partial}{\partial x} (2 x^{2} + 1 2^{2})

What is the derivative of ln(1-x^3) ?
The derivative of ln(1-x^3) is -(3x^2)/(1-x^3)
What is the first derivative of ln(1-x^3) ?
The first derivative of ln(1-x^3) is -(3x^2)/(1-x^3)