What is the sum from n=1 to infinity of 1/(e^{1/n)} ?

The sum from n=1 to infinity of 1/(e^{1/n)} is diverges

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sum from n=1 to infinity of 1/(e^{1/n)}

n = 1 \sum \infty \frac{1}{e ^{\frac{1}{n}}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{e ^{\frac{1}{n}}}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of 1/(e^{1/n)} ?
The sum from n=1 to infinity of 1/(e^{1/n)} is diverges