What is the derivative of y=cos^2(e^{cos^2(t)}) ?

The derivative of y=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)

What is the first derivative of y=cos^2(e^{cos^2(t)}) ?

The first derivative of y=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)

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derivative of

y = cos^{2} (e^{c o s^{2} (t)})

e^{c o s^{2} (t)} sin (2 e^{c o s^{2} (t)}) sin (2 t)

Solution steps

\frac{d}{d t} (cos^{2} (e^{c o s^{2} (t)}))

Apply the chain rule:

2 cos (e^{c o s^{2} (t)}) \frac{d}{d t} (cos (e^{c o s^{2} (t)}))

= 2 cos (e^{c o s^{2} (t)}) \frac{d}{d t} (cos (e^{c o s^{2} (t)}))

\frac{d}{d t} (cos (e^{c o s^{2} (t)})) = e^{c o s^{2} (t)} sin (e^{c o s^{2} (t)}) sin (2 t)

= 2 cos (e^{c o s^{2} (t)}) e^{c o s^{2} (t)} sin (e^{c o s^{2} (t)}) sin (2 t)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= e^{c o s^{2} (t)} sin (2 e^{c o s^{2} (t)}) sin (2 t)

\int \frac{( 1 + x )}{1 - x} d x

49 y^{^{''}} + 126 y^{^{'}} + 97 y = 0

\frac{1}{d ^{7}}

h (x) = (4 x + 6)^{x}

x \to - 2 lim (3^{x^{2 + 1}})

What is the derivative of y=cos^2(e^{cos^2(t)}) ?
The derivative of y=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)
What is the first derivative of y=cos^2(e^{cos^2(t)}) ?
The first derivative of y=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)