What is the tangent of 3x^2+2x-10 ?

The tangent of 3x^2+2x-10 is y=(6a_{0}+2)x-3a_{0}^2-10

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tangent of 3x^2+2x-10

tangent of

3 x^{2} + 2 x - 10

y = (6 a_{0} + 2) x - 3 a_{0}^{2} - 10

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} + 2 a_{0} - 10)

Find the slope of

y = 3 x^{2} + 2 x - 10 : \frac{d y}{d x} = 6 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0} + 2

Find the line with slope m=

6 a_{0} + 2

and passing through

(a_{0}, 3 a_{0}^{2} + 2 a_{0} - 10) : y = (6 a_{0} + 2) x - 3 a_{0}^{2} - 10

y = (6 a_{0} + 2) x - 3 a_{0}^{2} - 10

\frac{( 2 s + 1 )}{s ( s + 1 ) ^{2}}

y = x^{s i n (x)}

y^{^{''}} - 8 y^{^{'}} + 16 y = 0, y (0) = - 4, y^{^{'}} (0) = 0

6 x^{2} - x^{3}

\int \frac{5.45}{( 1 + 1.9 x ) ^{0.9}} d x

What is the tangent of 3x^2+2x-10 ?
The tangent of 3x^2+2x-10 is y=(6a_{0}+2)x-3a_{0}^2-10