What is the derivative of 2/(x^2-5x) ?

The derivative of 2/(x^2-5x) is -4/(x^3)-5

What is the first derivative of 2/(x^2-5x) ?

The first derivative of 2/(x^2-5x) is -4/(x^3)-5

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\frac{d}{d x} (\frac{2}{x ^{2}} - 5 x)

- \frac{4}{x ^{3}} - 5

Solution steps

\frac{d}{d x} (\frac{2}{x ^{2}} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x ^{2}}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (\frac{2}{x ^{2}}) = - \frac{4}{x ^{3}}

\frac{d}{d x} (5 x) = 5

= - \frac{4}{x ^{3}} - 5

\frac{d}{d x} (- \frac{9}{( 6 x + 3 ) ^{\frac{3}{2}}})

g (x) = x^{2} (1 - 2 x)

\frac{\partial}{\partial x} (x - y)

\frac{d}{d x} (sin (7 x + 2))

\int e^{2 x} sin (e^{x}) d x

What is the derivative of 2/(x^2-5x) ?
The derivative of 2/(x^2-5x) is -4/(x^3)-5
What is the first derivative of 2/(x^2-5x) ?
The first derivative of 2/(x^2-5x) is -4/(x^3)-5