What is (\partial)/(\partial x)(-cos(xy)) ?

The answer to (\partial)/(\partial x)(-cos(xy)) is ysin(xy)

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(\partial)/(\partial x)(-cos(xy))

\frac{\partial}{\partial x} (- cos (x y))

y sin (x y)

Solution steps

\frac{\partial}{\partial x} (- cos (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{\partial}{\partial x} (x y)

= - sin (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= - (- sin (x y) y)

Simplify

= y sin (x y)

\int \frac{1}{v} d v

\frac{2}{3 x ^{2}}

y^{^{'}} = \frac{y + x}{y - x}

y = \frac{3}{x}, y = \frac{3}{x ^{2}}, x = 7

\int \frac{1}{X} d X

What is (\partial)/(\partial x)(-cos(xy)) ?
The answer to (\partial)/(\partial x)(-cos(xy)) is ysin(xy)