What is (\partial)/(\partial x)(x*a+b) ?

The answer to (\partial)/(\partial x)(x*a+b) is a

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(\partial)/(\partial x)(x*a+b)

\frac{\partial}{\partial x} (x \cdot a + b)

a

Solution steps

\frac{\partial}{\partial x} (x a + b)

Treat

a, b

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x a) + \frac{\partial}{\partial x} (b)

\frac{\partial}{\partial x} (x a) = a

\frac{\partial}{\partial x} (b) = 0

= a + 0

Simplify

= a

y = \frac{x - 1}{x - 2} + 1, (3, 3)

ln (x^{2} + y) - x y^{2} = 10

\frac{cos ( x )}{1 + a \cdot sin ( x )}

\int 14 e^{- 14 x} d x

\int x^{3} - \frac{1}{2} x^{2} + 4 d x

What is (\partial)/(\partial x)(x*a+b) ?
The answer to (\partial)/(\partial x)(x*a+b) is a