What is the tangent of f(x)=e^x(x^4+3),(0,3) ?

The tangent of f(x)=e^x(x^4+3),(0,3) is y=3x+3

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tangent of f(x)=e^x(x^4+3),(0,3)

tangent of

f (x) = e^{x} (x^{4} + 3), (0, 3)

y = 3 x + 3

Solution steps

Find the slope of

f (x) = e^{x} (x^{4} + 3) : \frac{df ( x )}{d x} = e^{x} (x^{4} + 3) + 4 x^{3} e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(0, 3) : y = 3 x + 3

y = 3 x + 3

\frac{d}{d x} (\frac{x ^{2} - 10 x + 9}{( x - 5 ) ^{2}})

f (x) = \frac{4}{2 - x}

- \frac{36 ( x - 1 )}{( x + 3 ) ^{3}}

2 x^{2} + 5, - 2, 3

\int sin (3 θ) d θ

What is the tangent of f(x)=e^x(x^4+3),(0,3) ?
The tangent of f(x)=e^x(x^4+3),(0,3) is y=3x+3