What is the derivative of (2x^2+3^2) ?

The derivative of (2x^2+3^2) is 8x(2x^2+3)

What is the first derivative of (2x^2+3^2) ?

The first derivative of (2x^2+3^2) is 8x(2x^2+3)

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\frac{d}{d x} ((2 x^{2} + 3)^{2})

8 x (2 x^{2} + 3)

Solution steps

\frac{d}{d x} ((2 x^{2} + 3)^{2})

Apply the chain rule:

2 (2 x^{2} + 3) \frac{d}{d x} (2 x^{2} + 3)

= 2 (2 x^{2} + 3) \frac{d}{d x} (2 x^{2} + 3)

\frac{d}{d x} (2 x^{2} + 3) = 4 x

= 2 (2 x^{2} + 3) \cdot 4 x

Simplify

= 8 x (2 x^{2} + 3)

\frac{2}{s + 1} + 8 a \cdot \frac{s}{s ^{2} + 9}

\frac{d}{d x} ((1 - 2 x)^{5} (3 x - 2)^{6})

2 e^{2 t} + 8 t e^{2 t} + 4 t^{2} e^{2 t}

\frac{d}{d x} (\frac{ln ( x )}{2 x})

\frac{d}{d x} (\frac{6 - 7 x}{2 + x})

What is the derivative of (2x^2+3^2) ?
The derivative of (2x^2+3^2) is 8x(2x^2+3)
What is the first derivative of (2x^2+3^2) ?
The first derivative of (2x^2+3^2) is 8x(2x^2+3)