What is the derivative of y= 1/(ln(x)) ?

The derivative of y= 1/(ln(x)) is -1/(xln^2(x))

What is the first derivative of y= 1/(ln(x)) ?

The first derivative of y= 1/(ln(x)) is -1/(xln^2(x))

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derivative of

y = \frac{1}{ln ( x )}

- \frac{1}{x ln ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{1}{ln ( x )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (ln^{- 1} (x))

Apply the chain rule:

- \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

= - \frac{1}{( ln ( x ) ) ^{2}} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - \frac{1}{( ln ( x ) ) ^{2}} \cdot \frac{1}{x}

Simplify

- \frac{1}{ln ^{2} ( x )} \cdot \frac{1}{x} : - \frac{1}{x ln ^{2} ( x )}

= - \frac{1}{x ln ^{2} ( x )}

\int 51 sec^{4} (x) d x

\int \frac{2 x}{( x - 1 ) ^{5}} d x

\frac{d}{d x} (\frac{3}{1 - x})

f (t) = ln (t)

\int 2^{s i n (x)} cos (x) d x

What is the derivative of y= 1/(ln(x)) ?
The derivative of y= 1/(ln(x)) is -1/(xln^2(x))
What is the first derivative of y= 1/(ln(x)) ?
The first derivative of y= 1/(ln(x)) is -1/(xln^2(x))