What is the derivative of 1-ln(1-x) ?

The derivative of 1-ln(1-x) is 1/(-x+1)

What is the first derivative of 1-ln(1-x) ?

The first derivative of 1-ln(1-x) is 1/(-x+1)

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\frac{d}{d x} (1 - ln (1 - x))

\frac{1}{- x + 1}

Solution steps

\frac{d}{d x} (1 - ln (1 - x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (ln (1 - x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (1 - x)) = - \frac{1}{1 - x}

= 0 - (- \frac{1}{1 - x})

Simplify

= \frac{1}{- x + 1}

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What is the derivative of 1-ln(1-x) ?
The derivative of 1-ln(1-x) is 1/(-x+1)
What is the first derivative of 1-ln(1-x) ?
The first derivative of 1-ln(1-x) is 1/(-x+1)