What is the sum from n=1 to infinity of 5/(2^n+1) ?

The sum from n=1 to infinity of 5/(2^n+1) is converges

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sum from n=1 to infinity of 5/(2^n+1)

n = 1 \sum \infty \frac{5}{2 ^{n} + 1}

converges

Solution steps

n = 1 \sum \infty \frac{5}{2 ^{n} + 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{2 ^{n} + 1}

Apply Series Ratio Test:

converges

= 5 converges

= converges

\frac{\partial}{\partial x} (\frac{( x y )}{x + y})

\int_{- \infty}^{- 1} e^{- 24 t} d t

\int 15 x d x

\int_{0}^{1} \frac{1}{x ^{- 1}} d x

\int (\frac{5}{x}) d x

What is the sum from n=1 to infinity of 5/(2^n+1) ?
The sum from n=1 to infinity of 5/(2^n+1) is converges