What is the solution for 2sqrt(x)y^'=cos^2(y) ?

The solution for 2sqrt(x)y^'=cos^2(y) is y=arctan(sqrt(x)+c_{1})+pin

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2sqrt(x)y^'=cos^2(y)

2 x y^{^{'}} = cos^{2} (y)

y = arctan (x + c_{1}) + πn

Solution steps

2 x y^{'} (x) = cos^{2} (y)

Solve separable ODE:

y = arctan (x + c_{1}) + πn

y = arctan (x + c_{1}) + πn

9 x^{8} e^{x} + x^{9} e^{x}

\int 16 e^{- 4 x} sin (4 x) d x

- 6 s

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\frac{1}{2 + x}, 0

What is the solution for 2sqrt(x)y^'=cos^2(y) ?
The solution for 2sqrt(x)y^'=cos^2(y) is y=arctan(sqrt(x)+c_{1})+pin