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Popular >

derivative of 0.08e^xx^2

Solution

derivative of

0.08 e^{x} x^{2}

Solution

0.08 (e^{x} x^{2} + 2 x e^{x})

Solution steps

\frac{d}{d x} (0.08 e^{x} x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.08 \frac{d}{d x} (e^{x} x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = x^{2}

= 0.08 (\frac{d}{d x} (e^{x}) x^{2} + \frac{d}{d x} (x^{2}) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= 0.08 (e^{x} x^{2} + 2 x e^{x})

Graph

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Frequently Asked Questions (FAQ)

What is the derivative of 0.08e^xx^2 ?
The derivative of 0.08e^xx^2 is 0.08(e^xx^2+2xe^x)
What is the first derivative of 0.08e^xx^2 ?
The first derivative of 0.08e^xx^2 is 0.08(e^xx^2+2xe^x)