What is the solution for (dy)/(dx)(y+4)=2xy+4y ?

The solution for (dy)/(dx)(y+4)=2xy+4y is y=4\W(1/(4e^{(-x^2-4x-c_{1))/4}})

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(dy)/(dx)(y+4)=2xy+4y

\frac{d y}{d x} (y + 4) = 2 x y + 4 y

y = 4 W (\frac{1}{4 e ^{\frac{- x ^{2} - 4 x - c _{1}}{4}}})

Solution steps

\frac{d y}{d x} (y + 4) = 2 x y + 4 y

Solve separable ODE:

y = 4 W (\frac{1}{4 e ^{\frac{- x ^{2} - 4 x - c _{1}}{4}}})

y = 4 W (\frac{1}{4 e ^{\frac{- x ^{2} - 4 x - c _{1}}{4}}})

(x y^{^{'}} - y) cos (\frac{y}{x}) + x = 0

\frac{d}{d x} (cos (\frac{x ^{3}}{10}))

\frac{d y}{d x} = \frac{( x - 3 ) ^{2}}{x}

x \cdot \frac{d y}{d x} = \frac{1}{y ^{2}} + y

n = 1 \sum \infty \frac{1}{n ^{2} + 5 n + 6}

What is the solution for (dy)/(dx)(y+4)=2xy+4y ?
The solution for (dy)/(dx)(y+4)=2xy+4y is y=4\W(1/(4e^{(-x^2-4x-c_{1))/4}})