What is the derivative of 4+ln(x) ?

The derivative of 4+ln(x) is 1/x

What is the first derivative of 4+ln(x) ?

The first derivative of 4+ln(x) is 1/x

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\frac{d}{d x} (4 + ln (x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (4 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (4) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

y^{^{'}} = y (x y^{6} + 1)

\int_{0}^{17} 2 π x (17 x - x^{2}) d x

x \to a lim (\frac{sec ( x ) - sec ( a )}{x - a})

\int (\frac{7}{x} + 7 x) d x

y = 6 - ln (x + 1), y = ln (x + 1), x = 0

What is the derivative of 4+ln(x) ?
The derivative of 4+ln(x) is 1/x
What is the first derivative of 4+ln(x) ?
The first derivative of 4+ln(x) is 1/x