What is the sum from n=0 to infinity of-1/(5^n) ?

The sum from n=0 to infinity of-1/(5^n) is -5/4

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sum from n=0 to infinity of-1/(5^n)

n = 0 \sum \infty - \frac{1}{5 ^{n}}

- \frac{5}{4}

Solution steps

n = 0 \sum \infty - \frac{1}{5 ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - n = 0 \sum \infty \frac{1}{5 ^{n}}

Apply Series Geometric Test:

\frac{5}{4}

= - \frac{5}{4}

11 x^{2} y + \frac{d y}{d x} = - 6 x^{2}

x \to - 5 lim (\frac{x + 5}{x + 5})

\int ln (x^{- 2}) d x

\int \frac{8}{3} sin (x) d x

x \to - 4 lim (\frac{1}{4} x^{5} - 2 x)

What is the sum from n=0 to infinity of-1/(5^n) ?
The sum from n=0 to infinity of-1/(5^n) is -5/4