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Popular >

y^'= t/y

Solution

y^{^{'}} = \frac{t}{y}

Solution

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

Solution steps

y^{'} (t) = \frac{t}{y}

Solve separable ODE:

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

y = t^{2} + c_{1}, y = - t^{2} + c_{1}

Graph

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\int_{0}^{1} - e^{- x} d x

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Frequently Asked Questions (FAQ)

What is the solution for y^'= t/y ?
The solution for y^'= t/y is y=sqrt(t^2+c_{1)},y=-sqrt(t^2+c_{1)}